There are hundreds of questions on StackOverflow that all ask variations of the same thing. Paraphrasing:
lst is a list of strings and numbers. I want to convert the numbers to int but leave the strings alone. How do I do that?
This immediately gets a half-dozen answers that all do some equivalent of:
    lst = [int(x) if x.isdigit() else x for x in lst]
This has a number of problems, but they all come down to the same two:
  • "Numbers" is vague. You can assume it means only integers based on "I want to convert the numbers to int", but does it mean Python integer literals, things that can be converted with the int function with no base, or things that can be converted with the int function with base=0, or something different entirely, like JSON numbers or Excel numbers or the kinds of input you expect your 3rd-grade class to enter?
  • Whichever meaning you actually wanted, isdigit() does not test for that.
The right answer depends on what "numbers" actually means.

If it means "things that can be converted with the int function with no base", the right answer—as usual in Python—is to just try to convert with the int function:
    def tryint(x):
        try:
            return int(x)
        except ValueError:
            return x
    lst = [tryint(x) for x in lst]
Of course if you mean something different, that's not the right answer. Even "valid integer literals in Python source" isn't the same rule. (For example, 099 is an invalid literal in both 2.x and 3.x, and 012 is valid in 2.x but probably not what you wanted, but int('099') and int('0123') gives 99 and 123.) That's why you have to actually decide on a rule that you want to apply; otherwise, you're just assuming that all reasonable rules are the same, which is a patently false assumption. If your rule isn't actually "things that can be converted with the int function with no base, then the isdigit check is wrong, and the int(x) conversion is also wrong.

What specifically is wrong with isdigit?

I'm going to assume that you already thought through what you meant by "number", and the decision was "things that can be converted to int with the int function with no base", and you're just looking for how to LBYL that so you don't have to use a try.

Negative numbers

Obviously, -234 is an integer, but just as obviously, "-234".isdigit() is clearly going to be false, because - is not a digit.

Sometimes people try to solve this by writing all(c.isdigit() or c == '-' for c in x). But, besides being a whole lot slower and more complicated, that's even more wrong. It means that 123-456 now looks like an integer, so you're going to pass it to int without a try, and you're going to get a ValueError from your comprehension.

Of course you can solve that problem with (x[0].isdigit() or x[0] == '-') and x[1:].isdigit(), and now maybe every test you've thought of passes. But it will give you "1" instead of converting that to an integer, and it will raise an IndexError for an empty string.

One of these might be correct for handling negative integer numerals:
    x.isdigit() or x.startswith('-') and x[1:].isdigit()
    re.match(r'-?\d+', x)?
But is it obvious that either one is correct? The whole reason you wanted to use isdigit is to have something simple, obviously right, and fast, and you already no longer have that. And we're not even nearly done yet.

Positive numbers

+234 is an integer too. And int will treat it as one. But the code above won't. So now, whatever you did for -, you have to do the same thing for +. WHich is pretty ugly if you're using the non-regex solution:
    lst = [int(x) if x.isdigit() or x.startswith(('-', '+')) and x[1:].isdigit() else x
           for x in lst]

Whitespace

The int function allows the numeral to be surrounded by whitespace. But isdigit does not. So, now you have to add .strip() before the isdigit() call. Except we don't just have one isdigit call; to fix the other problems we've had two go with two isdigit calls and a startswith, and surely you don't want to call strip three times. Or we've switched to a regex. Either way, now we've got:
    lst = [int(x) if x.isdigit() or x.startswith(('-', '+')) and x[1:].isdigit() else x
           for x in (x.strip() for x in lst)]
    lst = [int(x) if re.match('\s*[+-]?\d+\s*', x) else x for x in lst]

What's a digit?

The isdigit function tests for characters that are in the Number, Decimal Digit category. In Python 3.x, that's the same rule the int function uses.

But 2.x doesn't use the same rule. If you're using a unicode, it's not entirely clear what int accepts, but it's not all Unicode digits, at least not in all Python 2.x implementations and versions; if you're using a str encoded in your default encoding, int still accepts the same set of digits, but isdigit only checks ASCII digits.

Plus, if you're using either 2.x or 3.0-3.2, and you've got a "narrow" Python build (like the default builds for Windows from python.org), isdigit is actually checking each UTF-16 code point, not each character, so for "\N{MATHEMATICAL SANS-SERIF DIGIT ZERO}", isdigit will return False, but int should accept it.

So, if your user types in an Arabic number like ١٠٤, the isdigit check may mean you end up with "١٠٤", or it may mean you end up with the int 104, or it may be one on some platforms and the other on other platforms.

I can't even think of any way to LBYL around this problem except to just say that your code requires 3.3+.

Have I thought of everything?

I don't know. Do you know? If you don't how are you going to write code that handles the things we haven't thought of.

Other rules might be even more complicated than the int with no base rule. For different use cases, users might reasonably expect 0x1234 or 1e10 or 1.0 or 1+0j or who knows what else to count as integers. The way to test for whatever it is you want to test for is still simple: write a conversion function for that, and see if it fails. Trying to LBYL it means that you have to write most of the same logic twice. Or, if you're relying on int or literal_eval or whatever to provide some or all of that logic, you have to duplicate its logic.
2

View comments

It's been more than a decade since Typical Programmer Greg Jorgensen taught the word about Abject-Oriented Programming.

Much of what he said still applies, but other things have changed. Languages in the Abject-Oriented space have been borrowing ideas from another paradigm entirely—and then everyone realized that languages like Python, Ruby, and JavaScript had been doing it for years and just hadn't noticed (because these languages do not require you to declare what you're doing, or even to know what you're doing). Meanwhile, new hybrid languages borrow freely from both paradigms.

This other paradigm—which is actually older, but was largely constrained to university basements until recent years—is called Functional Addiction.
5

I haven't posted anything new in a couple years (partly because I attempted to move to a different blogging platform where I could write everything in markdown instead of HTML but got frustrated—which I may attempt again), but I've had a few private comments and emails on some of the old posts, so I decided to do some followups.

A couple years ago, I wrote a blog post on greenlets, threads, and processes.
6

Looking before you leap

Python is a duck-typed language, and one where you usually trust EAFP ("Easier to Ask Forgiveness than Permission") over LBYL ("Look Before You Leap"). In Java or C#, you need "interfaces" all over the place; you can't pass something to a function unless it's an instance of a type that implements that interface; in Python, as long as your object has the methods and other attributes that the function needs, no matter what type it is, everything is good.
1

Background

Currently, CPython’s internal bytecode format stores instructions with no args as 1 byte, instructions with small args as 3 bytes, and instructions with large args as 6 bytes (actually, a 3-byte EXTENDED_ARG followed by a 3-byte real instruction). While bytecode is implementation-specific, many other implementations (PyPy, MicroPython, …) use CPython’s bytecode format, or variations on it.

Python exposes as much of this as possible to user code.
6

If you want to skip all the tl;dr and cut to the chase, jump to Concrete Proposal.

Why can’t we write list.len()? Dunder methods C++ Python Locals What raises on failure? Method objects What about set and delete? Data members Namespaces Bytecode details Lookup overrides Introspection C API Concrete proposal CPython Analysis

Why can’t we write list.len()?

Python is an OO language. To reverse a list, you call lst.reverse(); to search a list for an element, you call lst.index().
8

Many people, when they first discover the heapq module, have two questions:

Why does it define a bunch of functions instead of a container type? Why don't those functions take a key or reverse parameter, like all the other sorting-related stuff in Python? Why not a type?

At the abstract level, it's often easier to think of heaps as an algorithm rather than a data structure.
1

Currently, in CPython, if you want to process bytecode, either in C or in Python, it’s pretty complicated.

The built-in peephole optimizer has to do extra work fixing up jump targets and the line-number table, and just punts on many cases because they’re too hard to deal with. PEP 511 proposes a mechanism for registering third-party (or possibly stdlib) optimizers, and they’ll all have to do the same kind of work.
3

One common "advanced question" on places like StackOverflow and python-list is "how do I dynamically create a function/method/class/whatever"? The standard answer is: first, some caveats about why you probably don't want to do that, and then an explanation of the various ways to do it when you really do need to.

But really, creating functions, methods, classes, etc. in Python is always already dynamic.

Some cases of "I need a dynamic function" are just "Yeah? And you've already got one".
1

A few years ago, Cesare di Mauro created a project called WPython, a fork of CPython 2.6.4 that “brings many optimizations and refactorings”. The starting point of the project was replacing the bytecode with “wordcode”. However, there were a number of other changes on top of it.

I believe it’s possible that replacing the bytecode with wordcode would be useful on its own.
1

Many languages have a for-each loop. In some, like Python, it’s the only kind of for loop:

for i in range(10): print(i) In most languages, the loop variable is only in scope within the code controlled by the for loop,[1] except in languages that don’t have granular scopes at all, like Python.[2]

So, is that i a variable that gets updated each time through the loop or is it a new constant that gets defined each time through the loop?

Almost every language treats it as a reused variable.
4
Blog Archive
About Me
About Me
Loading
Dynamic Views theme. Powered by Blogger. Report Abuse.